NCERT Science Class 9 Chapter 4 Question Answer Solutions – Structure oF The Atom FREE PDF Download
Page – 39
โจ Q.1. What are Canal Rays? โก๐ฌ๐ก
Answer:-
โจ Canal Rays โก๐ฌ
Definition:
Canal rays, also known as anode rays โ๐, are positively charged radiations that were discovered by Eugen Goldstein in 1886. These rays consist of positively charged particles, later identified as protons ๐งชโ๏ธ.
๐ Discovery & Explanation
Goldstein observed that when a perforated cathode ๐ณ๏ธ was used in a discharge tube filled with gas, a new type of rays moved in the opposite direction of cathode rays. Since these rays passed through the canals (holes) in the cathode, they were named Canal Rays ๐โจ.
โก Characteristics of Canal Rays
โ
Positively charged particles โ๐
โ
Move in the opposite direction of cathode rays ๐
โ
Deflected by electric and magnetic fields ๐งฒโก
โ
Have mass and occupy space โ๏ธ๐
โ
Led to the discovery of protons ๐๐ฌ
๐ Importance in Atomic Structure
The discovery of canal rays played a crucial role in understanding atomic structure ๐งชโ๏ธ. It helped scientists identify protons, which are present in the nucleus of an atom ๐ก๐ฌ.
๐ก Conclusion: Canal rays are an essential discovery in atomic physics, as they provided evidence of positively charged particles in atoms, leading to the development of modern atomic models.
โจ Q.2. If an atom contains one electron โกโ and one proton ๐โ, will it carry any charge or not? โ๏ธ๐ก
Answer:-
โ๏ธ Charge on an Atom with One Electron and One Proton
An atom consists of subatomic particles ๐งช๐ฌ, including electrons โกโ (negatively charged) and protons ๐โ (positively charged).
If an atom contains one electron โก and one proton ๐, the negative charge of the electron cancels out the positive charge of the proton. Since both charges are equal in magnitude but opposite in nature, the atom remains electrically neutral โ๏ธ๐.
๐ Key Explanation:
โ
Electron (-1 charge) + Proton (+1 charge) = Net charge = 0 โ๏ธ
โ
No overall charge on the atom ๐ซโก
โ
Example: A hydrogen atom ๐กโ๏ธ consists of one electron and one proton, making it neutral.
๐ก Conclusion:
An atom with one electron and one proton does not carry any charge because the opposite charges balance each other. Hence, it is electrically neutral โ๏ธโจ.
Page – 41
โจ Q.1. On the basis of Thomsonโs model โ๏ธ๐ฌ of an atom, explain how the atom is neutral โ๏ธ๐ as a whole. ๐ก๐
Answer:-
โจ Thomsonโs Model of an Atom โ๏ธ๐ฌ
According to J.J. Thomson, an atom is like a plum pudding ๐ฎ or a watermelon ๐, where:
๐ด The positively charged matter (protons) is spread throughout the atom, just like the soft, red part of a watermelon.
โซ The negatively charged electrons are embedded within it, just like the black seeds in a watermelon!
โ๏ธ Why is the Atom Neutral as a Whole? ๐
An atom consists of:
๐ Positively charged protons (+) spread uniformly.
โก Negatively charged electrons (โ) scattered throughout.
Since the total positive charge is equal to the total negative charge, they balance each other out. ๐ As a result, the atom remains electrically neutral โ๏ธโneither positively nor negatively charged!
๐ฏ Board Exam Tip:
Write this answer neatly ๐๏ธ, add a simple diagram ๐ of Thomson’s atomic model, and use proper scientific terms to get full marks โ
!
โจ Q.2. On the basis of Rutherfordโs model ๐ฌโ๏ธ of an atom, which subatomic particle ๐๐งช is present in the nucleus ๐ก๐ of an atom? ๐ก
Answer:-
โจ Rutherfordโs Model of an Atom ๐ฌโ๏ธ
The gold foil experiment ๐ conducted by Ernest Rutherford led to the discovery of a new atomic model!
๐ก The Nucleus โ A Dense Core ๐
According to Rutherford:
๐น An atom has a small, dense, positively charged nucleus ๐ก at its center.
๐น Electrons โก revolve around this nucleus in circular orbits, just like planets around the Sun! ๐๐ช
๐ Which Subatomic Particle is Present in the Nucleus? ๐งช
๐ The nucleus contains positively charged particles called protons โโ๏ธ!
๐ Later, scientists discovered neutrons ๐ฌ, which are also present inside the nucleus but carry no charge โช.
๐ Board Exam Tip:
โ
Mention Rutherfordโs gold foil experiment ๐.
โ
Draw a simple labeled diagram ๐ to illustrate the atomic structure.
โ
Use precise scientific terms and maintain clarity in your explanation!
โจ Q.3. Draw a sketch ๐๏ธ๐ of Bohrโs model โ๏ธ๐ฌ of an atom with three shells ๐โฐโฐ. ๐ก
Answer:-
โจ Q.4. What do you think ๐ค๐ก would be the observation ๐๐ฌ if the ฮฑ-particle scattering experiment โ๏ธโจ is carried out using a foil ๐๏ธ๐ of a metal other than gold? ๐ญ๐
Answer:-
โจ Observations of the ฮฑ-Particle Scattering Experiment Using a Different Metal Foil โ๏ธโจ
In Rutherfordโs ฮฑ-particle scattering experiment ๐ฌโจ, gold foil ๐๏ธ๐ was used because:
- Gold is highly malleable ๐, allowing it to be beaten into extremely thin layers.
- Gold atoms are relatively large โ๏ธ, making it easier to observe scattering patterns.
๐ก What Would Happen with Another Metal Foil? ๐
If the experiment were carried out using a different metal foil ๐๏ธ๐, the observations would depend on the metalโs atomic properties:
1๏ธโฃ Similar Observations โ
If the metal has a large atomic size โ๏ธ and can be beaten into a thin foil, the results would be similar:
๐ธ Most ฮฑ-particles โก would pass straight through ๐ก.
๐ธ Some would deflect at small angles ๐.
๐ธ A very few would bounce back โฌ
๏ธ due to hitting the dense nucleus ๐ก.
2๏ธโฃ Different Observations โ
If the metal has a smaller atomic size โ๏ธ or cannot be made into a thin foil, then:
๐น More ฮฑ-particles might be deflected because of tightly packed nuclei ๐.
๐น Fewer ฮฑ-particles would pass through ๐ก if the metal is not as malleable.
๐น Scattering patterns would differ, affecting Rutherfordโs conclusions about the atomic nucleus! ๐กโ๏ธ
๐ฏ Board Exam Tip:
โ
Mention why gold was used ๐๏ธ๐.
โ
Explain how atomic properties affect the experiment ๐.
โ
Draw a simple labeled diagram โ๏ธโ๏ธ to show ฮฑ-particle paths!
Page – 41
โจ Q.1. Name the three sub-atomic particles โ๏ธ๐ฌ of an atom. ๐โโ๏ธ
Answer:-
โจ Three Sub-Atomic Particles of an Atom โ๏ธ๐ฌ
An atom consists of three fundamental sub-atomic particles:
1๏ธโฃ Proton โโ๏ธ
๐น Located in the nucleus ๐ก๐
๐น Has a positive charge (+1) โก
๐น Determines the atomic number of an element ๐ท๏ธ๐ข
2๏ธโฃ Neutron โช๐ฌ
๐น Also found in the nucleus ๐ก
๐น Has no charge (neutral) โ๏ธ
๐น Contributes to the mass of the atom โ๏ธ๐งฎ
3๏ธโฃ Electron โกโ
๐น Revolves around the nucleus in shells or orbits ๐โฐ
๐น Has a negative charge (-1) โก
๐น Responsible for chemical bonding and reactions ๐งช๐ฅ
๐ฏ Board Exam Tip:
โ
Clearly define each particle with its charge, location, and role.
โ
Draw a labeled diagram โ๏ธ๐ of an atom showing protons, neutrons, and electrons.
โ
Keep explanations precise and well-structured to secure full marks ๐ฏ๐!
โจ Q.2. A helium atom โ๏ธ๐จ has an atomic mass of 4 u โ๏ธ๐ฌ and two protons ๐โ in its nucleus ๐ก๐. How many neutrons โซ๐ก does it have?
Answer:-
โจ Number of Neutrons in a Helium Atom โ๏ธ๐จ
A helium atom has:
๐น Atomic mass = 4 u โ๏ธ๐ฌ
๐น Number of protons = 2 ๐โ
๐งฎ Formula to Calculate Neutrons โซ๐ก
Neutrons = Atomic mass – Number of protons
๐ Substituting values:
Neutrons = 4 u – 2 โก 2 neutrons โซโซ
โ Final Answer:
A helium atom has 2 neutrons inside its nucleus ๐ก๐.
๐ฏ Board Exam Tip:
โ
Write the formula clearly.
โ
Show the step-by-step calculation ๐งฎ.
โ
Keep the explanation neat & precise ๐ for full marks ๐ฏ!
Page – 42
Q. 1. Write the distribution of electrons in carbon and sodium atoms.
Answer:-
โจ Electron Distribution in Carbon and Sodium Atoms โ๏ธ๐ฌ
In an atom, electrons โก are arranged in shells (energy levels) ๐โฐ around the nucleus ๐ก.
๐น Electron Distribution in Carbon (C) ๐๏ธโ๏ธ
๐ธ Atomic Number = 6 ๐ข
๐ธ Number of Electrons โก = 6
๐ Distribution:
K-shell (1st) โก 2 electrons โกโก
L-shell (2nd) โก 4 electrons โกโกโกโก
โ Electronic configuration of Carbon: 2, 4
๐น Electron Distribution in Sodium (Na) ๐๏ธโ๏ธ
๐ธ Atomic Number = 11 ๐ข
๐ธ Number of Electrons โก = 11
๐ Distribution:
K-shell (1st) โก 2 electrons โกโก
L-shell (2nd) โก 8 electrons โกโกโกโกโกโกโกโก
M-shell (3rd) โก 1 electron โก
โ Electronic configuration of Sodium: 2, 8, 1
๐ฏ Board Exam Tip:
โ
Write atomic numbers and electron arrangements clearly ๐๏ธ.
โ
Draw labeled diagrams โ๏ธ๐ showing shells and electrons.
โ
Keep the explanation precise and structured ๐ for full marks ๐ฏ!
Q. 2. If K and L shells of an atom are full, then what would be the total number of electrons in the atom?
Answer:-
โจ Total Number of Electrons When K and L Shells Are Full โ๏ธ๐ฌ
Electrons โก in an atom are arranged in shells (energy levels) ๐โฐ based on the Bohrโs atomic model!
๐ก Maximum Electrons in K and L Shells ๐ฌ
๐ธ K-shell (1st energy level): Can hold 2 electrons โกโก
๐ธ L-shell (2nd energy level): Can hold 8 electrons โกโกโกโกโกโกโกโก
โ Total Number of Electrons
If both K and L shells are full, the atom will have:
๐ 2 (K-shell) + 8 (L-shell) = 10 electrons โกโจ
Thus, the atom contains 10 electrons in total when its K and L shells are completely filled! ๐โ๏ธ
๐ฏ Board Exam Tip:
โ
Clearly explain electron arrangement ๐ก.
โ
Mention Bohrโs rule for maximum electrons in each shell! ๐ฌ๐
โ
Draw a simple labeled diagram โ๏ธ๐ showing K and L shell electron distribution.
Page – 44
Q. 1. How will you find the valency of chlorine, sulphur and magnesium?
Answer:-
โจ Finding the Valency of Chlorine, Sulphur, and Magnesium โ๏ธ๐ฌ
Valency refers to the combining capacity of an atom ๐๐. It depends on the number of electrons in the outermost shell ๐โฐ of an atom.
๐น Valency of Chlorine (Cl) ๐๏ธโ๏ธ
๐ธ Atomic Number = 17 ๐ข
๐ธ Electronic Configuration = 2, 8, 7 โกโกโฐโฐโฐโฐโฐ
๐ Valency = 8 โ Outer electrons = 8 โ 7 = 1
โ
Chlorine has a valency of 1 โโจ, meaning it needs 1 electron to complete its octet!
๐น Valency of Sulphur (S) ๐๏ธโ๏ธ
๐ธ Atomic Number = 16 ๐ข
๐ธ Electronic Configuration = 2, 8, 6 โกโกโฐโฐโฐโฐโฐโฐ
๐ Valency = 8 โ Outer electrons = 8 โ 6 = 2
โ
Sulphur has a valency of 2 โโจ, meaning it needs 2 electrons to complete its octet!
๐น Valency of Magnesium (Mg) ๐๏ธโ๏ธ
๐ธ Atomic Number = 12 ๐ข
๐ธ Electronic Configuration = 2, 8, 2 โกโกโฐโฐ
๐ Valency = Outer electrons = 2
โ
Magnesium has a valency of 2 โโจ, meaning it can lose 2 electrons to become stable!
๐ฏ Board Exam Tip:
โ
Write electron configurations clearly ๐๏ธ.
โ
Explain how valency is determined ๐.
โ
Draw a simple labeled diagram โ๏ธ๐ for visual clarity.
โ
Keep explanations structured and precise to secure full marks ๐ฏ๐!
Page – 44
Q. 1. If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?
Answer:-
โจ Atomic Number & Charge of the Atom โ๏ธ๐ฌ
Given:
๐น Number of electrons = 8 โก
๐น Number of protons = 8 ๐
(i) Atomic Number of the Atom ๐ขโ๏ธ
The atomic number of an element is the number of protons in its nucleus ๐ก.
๐ Since the atom has 8 protons, its atomic number = 8 โ
.
Thus, the element is Oxygen (O) ๐ฌ๏ธ!
(ii) Charge on the Atom โ๏ธ๐ก
- Protons (+) โก 8 positive charges โโโโโโโโ
- Electrons (-) โก 8 negative charges โโโโโโโโ
๐ Since positive and negative charges are equal, they cancel each other out, making the atom neutral โ๏ธ๐!
๐ฏ Board Exam Tip:
โ
Write definitions clearly ๐๏ธ.
โ
Show step-by-step explanation ๐งฎ.
โ
Keep answers neat & structured for full marks ๐ฏ๐!
Q. 2. With the help of Table 4.1, find out the mass number of oxygen and sulphur atom.
Answer:-
โจ Mass Number of Oxygen & Sulphur Atoms โ๏ธ๐ฌ
The mass number of an atom is calculated as:
๐ Mass Number = Number of Protons + Number of Neutrons โ๏ธ๐ก
๐น Mass Number of Oxygen (O) ๐ฌ๏ธโ๏ธ
๐ธ Atomic Number = 8 ๐ข
๐ธ Protons = 8 โ
๐ธ Neutrons = 8 โช
๐ Mass Number = 8 + 8 = 16
โ Oxygen has a mass number of 16 โ๏ธ๐!
๐น Mass Number of Sulphur (S) ๐๏ธโ๏ธ
๐ธ Atomic Number = 16 ๐ข
๐ธ Protons = 16 โ
๐ธ Neutrons = 16 โช
๐ Mass Number = 16 + 16 = 32
โ Sulphur has a mass number of 32 โ๏ธ๐!
๐ฏ Board Exam Tip:
โ
Clearly define mass number ๐.
โ
Show step-by-step calculations ๐งฎ.
โ
Keep answers precise & well-structured to ensure full marks ๐ฏ๐!
Page – 45
Q. 1. For the symbol H,D and T tabulate three sub-atomic particles found in each of them.
Answer:-
โจ Tabulation of Sub-Atomic Particles in Hydrogen (H), Deuterium (D), and Tritium (T) โ๏ธ๐ฌ
Hydrogen, Deuterium (heavy hydrogen), and Tritium (radioactive hydrogen) are isotopes ๐๏ธ of the same element, differing only in their number of neutrons!
๐ Table of Sub-Atomic Particles
Isotope โ๏ธ | Protons ๐โ | Neutrons โซ๐ก | Electrons โกโ |
---|---|---|---|
Hydrogen (H) ๐ฌ๏ธ | 1 | 0 | 1 |
Deuterium (D) ๐๏ธ | 1 | 1 | 1 |
Tritium (T) โก | 1 | 2 | 1 |
๐ฏ Board Exam Tip:
โ
Mention that H, D, and T are isotopes of hydrogen! โ๏ธ
โ
Clearly define and differentiate them in terms of neutrons.
โ
Use a well-structured table ๐ for clarity.
โ
Keep answers neat, concise, and precise for full marks ๐ฏ๐!
Q. 2. Write the electronic configuration of any one pair of isotopes and isobars.
Answer:-
โจ Electronic Configuration of Isotopes & Isobars โ๏ธ๐ฌ
Isotopes are atoms of the same element ๐๏ธ but with different numbers of neutrons โซ๐ก.
Isobars are atoms of different elements ๐ but with the same mass number โ๏ธ!
๐น Example of Isotopes: Carbon-12 (ยนยฒC) & Carbon-14 (ยนโดC)
โ
Both belong to Carbon (C) ๐๏ธ
โ
Atomic Number = 6 ๐ข (Same for both isotopes)
โ
Electronic Configuration = 2, 4 โกโฐโฐ
๐ Difference:
- ยนยฒC has 6 neutrons โช
- ยนโดC has 8 neutrons โชโช
Thus, isotopes have same electronic configuration but different neutron count! ๐
๐น Example of Isobars: Calcium-40 (โดโฐCa) & Argon-40 (โดโฐAr)
โ
Different elements (Ca & Ar) ๐
โ
Same mass number = 40 โ๏ธ
โ
Different atomic numbers ๐ข
๐ Electronic configurations:
- Calcium (โดโฐCa) โ๏ธ โก 2, 8, 8, 2 โกโฐโฐโฐโฐ
- Argon (โดโฐAr) ๐ โก 2, 8, 8 โกโฐโฐโฐ
๐ Difference:
- Calcium has 20 protons & 20 neutrons ๐โช
- Argon has 18 protons & 22 neutrons ๐โชโช
Thus, isobars have different electronic configurations but same mass number! ๐
๐ฏ Board Exam Tip:
โ
Clearly define isotopes & isobars ๐
โ
Show step-by-step electronic configurations ๐งฎ
โ
Use structured tables or diagrams โ๏ธ๐ for clarity
โ
Keep answers precise & well-organized to get full marks ๐ฏ๐
Chapter Back Excercise Question Answer
Q. 1. Compare the properties of electrons, protons and neutrons.
Answer:-
โจ Comparison of Electrons, Protons, and Neutrons โ๏ธ๐ฌ
Atoms are made up of three fundamental sub-atomic particles ๐. Each particle has unique properties that determine the behavior of an atom!
๐ Tabular Comparison
Property ๐๏ธ | Electron (โกโ) | Proton (๐โ) | Neutron (โช) |
---|---|---|---|
Charge โ๏ธ | Negative (-1) | Positive (+1) | Neutral (0) |
Location ๐ก | Revolves around nucleus in shells ๐โฐ | Inside nucleus ๐ก | Inside nucleus ๐ก |
Mass โ๏ธ | Very small (โ1/1836 u) | 1 atomic mass unit (u) | 1 atomic mass unit (u) |
Role ๐ก | Responsible for chemical reactions โ๏ธ๐งช | Determines atomic number ๐ข | Adds to atomic mass & stability โ๏ธ๐ |
๐ฏ Board Exam Tip:
โ
Use a neatly structured table ๐ for clarity!
โ
Mention charge, location, mass & role of each particle ๐.
โ
Keep the explanation precise to secure full marks ๐ฏ!
โ
Draw a labeled atomic structure diagram โ๏ธ๐ for a visual boost!
Q. 2. What are the limitations of J.J. Thomsonโs model of the atom?
Answer:-
โจ Limitations of J.J. Thomsonโs Model of the Atom โ๏ธ๐ฌ
J.J. Thomson proposed the Plum Pudding Model ๐ฎ of an atom, where:
๐น The atom was a positively charged sphere โก๐.
๐น Electrons โซ were embedded like raisins in a pudding ๐.
However, this model had several limitations that led to new discoveries! ๐
๐ด Major Limitations โ
1๏ธโฃ Could Not Explain Rutherfordโs Experiment ๐ฌโจ
๐ The ฮฑ-particle scattering experiment showed that atoms have a dense nucleus ๐ก, contradicting Thomsonโs model!
2๏ธโฃ Did Not Explain Atomic Structure โ๏ธ๐ก
๐ Thomsonโs model could not explain how electrons move or why they donโt collapse into the nucleus.
3๏ธโฃ Failed to Explain Nuclear Charge ๐โ๏ธ
๐ Rutherford’s model later proved that the positive charge is concentrated in the nucleus, not spread throughout the atom.
๐ฏ Board Exam Tip:
โ
Mention Thomsonโs Plum Pudding Model ๐ฎโ๏ธ.
โ
Clearly explain why Rutherfordโs experiment disproved it ๐โจ.
โ
Keep answers structured & precise for full marks ๐ฏ๐!
Q. 3. What are the limitations of Rutherfordโs model of the atom?
Answer:-
โจ Limitations of Rutherfordโs Model of the Atom ๐ฌโ๏ธ
Rutherfordโs gold foil experiment ๐ revealed the presence of a dense, positively charged nucleus ๐ก. His atomic model explained how electrons revolve around the nucleus, but it had some major limitations! ๐
๐ด Major Limitations of Rutherfordโs Model โ
1๏ธโฃ Could Not Explain Stability of Electrons โก๐
๐ According to classical physics, revolving electrons should lose energy and spiral into the nucleus! โ But atoms are stable, proving Rutherfordโs model incomplete.
2๏ธโฃ Did Not Explain Energy Levels ๐๐ก
๐ Rutherfordโs model did not explain why electrons stay in fixed orbits instead of continuously losing energy. Bohrโs model later introduced energy levels ๐โฐ.
3๏ธโฃ Failed to Describe Atomic Spectrum ๐โ๏ธ
๐ Rutherfordโs model did not explain why atoms emit specific spectral lines when excited! ๐ Bohrโs theory later solved this using quantized energy levels.
๐ฏ Board Exam Tip:
โ
Mention Rutherfordโs gold foil experiment ๐.
โ
Clearly explain why electrons should collapse but donโt ๐ฌ.
โ
Relate it to Bohrโs model improvements ๐.
โ
Keep your answer well-structured & precise for full marks ๐ฏ๐!
Q. 4. Describe Bohrโs model of the atom.
Answer:-
โจ Bohrโs Model of the Atom โ๏ธ๐ฌ
Niels Bohr proposed an improved atomic model ๐ that explained how electrons behave inside an atom!
๐น Key Features of Bohrโs Model โ๏ธ๐ก
1๏ธโฃ Electrons Revolve in Fixed Orbits ๐โฐ
๐ Electrons โก move around the nucleus ๐ก in specific circular paths (shells) instead of randomly!
2๏ธโฃ Energy Levels are Quantized ๐โจ
๐ Electrons stay in fixed energy levels ๐ and do not lose energy while revolving!
3๏ธโฃ Electrons Jump Between Energy Levels โก๐
๐ Electrons can absorb energy ๐ฅ and move to a higher level, or release energy ๐ to return to a lower level!
๐น Example: Bohrโs Model of Hydrogen (H) ๐ฌ๏ธ
โ
Single electron โก revolves around the nucleus ๐ก in a defined orbit ๐.
โ
The energy of the electron depends on its shell position!
๐ฏ Board Exam Tip:
โ
Mention that Bohrโs model improved Rutherfordโs theory.
โ
Explain energy levels, electron movement & stability.
โ
Draw a simple labeled diagram โ๏ธ๐ for visual clarity!
โ
Keep answers neat & structured to secure full marks ๐ฏ๐!
Q. 5. Compare all the proposed models of an atom given in this chapter.
Answer:-
โจ Comparison of All Proposed Atomic Models โ๏ธ๐ฌ
Over time, scientists developed different models to explain the structure of an atom ๐โก. Each model had strengths and limitations that helped refine our understanding! ๐
๐ Tabular Comparison of Atomic Models
Model ๐ฌ | Scientist ๐ | Key Features ๐ก | Limitations โ |
---|---|---|---|
Daltonโs Atomic Model โ๏ธ | John Dalton (1808) | ๐ Atoms are indivisible and cannot be created or destroyed. | โ Could not explain sub-atomic particles and atomic structure. |
Thomsonโs Model (Plum Pudding) ๐ฎ | J.J. Thomson (1897) | ๐ Atoms are positively charged spheres โก with embedded electrons โซ. | โ Failed to explain the existence of a nucleus and atomic stability. |
Rutherfordโs Model ๐ฌโจ | Ernest Rutherford (1911) | ๐ Atoms have a dense, positively charged nucleus ๐ก with electrons revolving around it. | โ Could not explain why electrons donโt lose energy and collapse into the nucleus. |
Bohrโs Model ๐โฐ | Niels Bohr (1913) | ๐ Electrons move in fixed energy levels ๐ and absorb/release energy when changing levels. | โ Could not explain subatomic interactions & wave behavior of electrons. |
Quantum Mechanical Model ๐โ๏ธ | Schrรถdinger & Heisenberg (1926) | ๐ Electrons exist in probability clouds (orbitals) rather than fixed paths. | โ Complex model, difficult to visualize atomic structure easily. |
๐ฏ Board Exam Tip:
โ
Use structured tables ๐ for better clarity!
โ
Mention scientists & key discoveries ๐.
โ
Explain how models evolved and their limitations.
โ
Keep answers well-organized to ensure full marks ๐ฏ๐!
Q. 6. Summarise the rules for writing of distribution of electrons in various shells for the first eighteen elements.
Answer:-
โจ Rules for Electron Distribution in Various Shells โ๏ธ๐ฌ
Electrons โก in an atom are arranged in shells (energy levels) ๐โฐ around the nucleus ๐ก. The distribution follows specific rules to determine the electronic configuration of an element.
๐น Rules for Electron Distribution ๐๐ก
1๏ธโฃ Maximum Electrons in a Shell ๐โจ
๐ The maximum number of electrons that a shell can hold is given by the formula:
2nยฒ (where n is the shell number)
โ
K-shell (n = 1) โก 2 ร (1ยฒ) = 2 electrons โกโก
โ
L-shell (n = 2) โก 2 ร (2ยฒ) = 8 electrons โกโกโกโกโกโกโกโก
โ
M-shell (n = 3) โก 2 ร (3ยฒ) = 18 electrons โกโกโกโกโกโกโกโกโกโกโกโกโกโกโกโกโกโก
2๏ธโฃ Outer Shell Cannot Hold More than 8 Electrons โ๏ธ๐ฌ
๐ Even though the M-shell can hold 18 electrons, it cannot have more than 8 electrons unless the next shell starts filling!
3๏ธโฃ Filling Order of Shells ๐โฐ
๐ Electrons fill shells in order of increasing energy levels:
K โ L โ M โ N ๐
๐น Example: Electron Distribution for First 18 Elements ๐งชโ๏ธ
Element ๐๏ธ | Atomic Number ๐ข | Electron Configuration โก |
---|---|---|
Hydrogen (H) ๐ฌ๏ธ | 1 | 1 |
Helium (He) ๐จ | 2 | 2 |
Lithium (Li) ๐ | 3 | 2, 1 |
Carbon (C) ๐๏ธ | 6 | 2, 4 |
Oxygen (O) ๐ฌ๏ธ | 8 | 2, 6 |
Sodium (Na) ๐๏ธ | 11 | 2, 8, 1 |
Chlorine (Cl) ๐ก | 17 | 2, 8, 7 |
Argon (Ar) ๐ | 18 | 2, 8, 8 |
๐ฏ Board Exam Tip:
โ
Use formula 2nยฒ to show maximum electrons in each shell!
โ
Clearly define rules for electron filling.
โ
Draw a labeled diagram โ๏ธ๐ of electron distribution!
โ
Keep answers structured & precise to secure full marks ๐ฏ๐!
Q. 7. Define valency by taking examples of silicon and oxygen.
Answer:-
โจ Definition of Valency with Examples of Silicon & Oxygen โ๏ธ๐ฌ
Valency refers to the combining capacity of an atom ๐๐. It is determined by the number of electrons present in the outermost shell ๐โฐ of an atom.
๐น Valency of Silicon (Si) ๐๏ธโ๏ธ
๐ธ Atomic Number = 14 ๐ข
๐ธ Electronic Configuration = 2, 8, 4 โกโกโฐโฐโฐโฐ
๐ Valency = 4 โโจ
โ Silicon needs 4 more electrons to complete its octet, making its valency 4!
๐ก Example: Si forms bonds with oxygen in silica (SiOโ)! ๐ฌ
๐น Valency of Oxygen (O) ๐ฌ๏ธโ๏ธ
๐ธ Atomic Number = 8 ๐ข
๐ธ Electronic Configuration = 2, 6 โกโกโฐโฐโฐโฐโฐโฐ
๐ Valency = 2 โโจ
โ Oxygen needs 2 more electrons to complete its octet, making its valency 2!
๐ก Example: Oxygen forms bonds in water (HโO) and carbon dioxide (COโ)! ๐ง๐
๐ฏ Board Exam Tip:
โ
Clearly define valency in simple terms.
โ
Show electron configurations to explain how valency is determined.
โ
Use real-life examples of compounds!
โ
Keep answers structured & precise to secure full marks ๐ฏ๐!
Hope this helps, Anurag! ๐โจ Let me know if you need refinements! ๐โ๏ธ๐ฌ
Q. 8. Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and iv) Isobars. Give any two uses of isotopes.
Answer:-
โจ Explanation with Examples: Atomic Number, Mass Number, Isotopes & Isobars โ๏ธ๐ฌ
Atoms are made up of protons, neutrons, and electrons ๐ก. Their characteristics are defined using atomic number, mass number, isotopes, and isobars! ๐
(i) Atomic Number (Z) ๐ขโ๏ธ
๐ Definition: The atomic number of an element is the number of protons ๐ in its nucleus ๐ก.
๐ Formula: Atomic Number (Z) = Number of Protons
๐ Example:
โ
Hydrogen (H) ๐ฌ๏ธ has 1 proton, so its atomic number = 1.
โ
Carbon (C) ๐๏ธ has 6 protons, so its atomic number = 6.
(ii) Mass Number (A) โ๏ธ๐ก
๐ Definition: The mass number of an atom is the sum of protons and neutrons present in the nucleus ๐ก.
๐ Formula: Mass Number (A) = Number of Protons + Number of Neutrons
๐ Example:
โ
Oxygen (O) ๐ฌ๏ธ has 8 protons and 8 neutrons, so its mass number = 16.
โ
Sulphur (S) ๐๏ธ has 16 protons and 16 neutrons, so its mass number = 32.
(iii) Isotopes โ๏ธ๐ฌ
๐ Definition: Isotopes are atoms of the same element that have the same atomic number but different mass numbers! ๐
๐ Example:
โ
Hydrogen Isotopes ๐ฌ๏ธ:
- Protium (ยนH): 1 proton, 0 neutrons, mass number = 1.
- Deuterium (ยฒH): 1 proton, 1 neutron, mass number = 2.
- Tritium (ยณH): 1 proton, 2 neutrons, mass number = 3.
(iv) Isobars โ๏ธโจ
๐ Definition: Isobars are atoms of different elements that have the same mass number but different atomic numbers! ๐
๐ Example:
โ
Calcium-40 (โดโฐCa) & Argon-40 (โดโฐAr):
- Calcium (Ca) โก Atomic Number = 20 ๐ข, Mass Number = 40.
- Argon (Ar) โก Atomic Number = 18 ๐ข, Mass Number = 40.
Uses of Isotopes ๐ฌ๐ก
๐ 1๏ธโฃ Medical Applications ๐ฅ
โ
Cobalt-60 (โถโฐCo) is used in cancer treatment (radiotherapy)!
โ
Iodine-131 (ยนยณยนI) is used to treat thyroid disorders!
๐ 2๏ธโฃ Industrial & Scientific Uses ๐๏ธ
โ
Carbon-14 (ยนโดC) is used in carbon dating to determine the age of fossils!
โ
Uranium-235 (ยฒยณโตU) is used in nuclear power plants!
๐ฏ Board Exam Tip:
โ
Clearly define each term and provide examples.
โ
Show calculations for atomic & mass number.
โ
Use a structured format to make answers clear & engaging!
โ
Diagrams & tables ๐๐ can add visual appeal!
Q. 9. Na+ has completely filled K and L shells. Explain.
Answer:-
โจ Explanation: Naโบ has Completely Filled K and L Shells โ๏ธ๐ฌ
Sodium (Na) ๐๏ธ has an atomic number of 11 ๐ข, meaning it has 11 electrons โก in its neutral state.
โ
Electronic Configuration of Neutral Na: 2, 8, 1 โฐโฐโฐ
๐น Formation of Naโบ Ion โกโจ
- Sodium loses 1 electron โก from its M-shell (third shell).
- This happens because atoms tend to achieve a stable electronic configuration (like noble gases ๐๐ก).
- After losing one electron, Naโบ has only 10 electrons left! โ
๐ New Electronic Configuration of Naโบ: 2, 8 โฐโฐ
โ
Now, only K and L shells are occupied and they are completely filled! ๐โจ
๐ฏ Board Exam Tip:
โ
Clearly explain how Naโบ is formed.
โ
Mention the stable configuration goal.
โ
Use a neat diagram โ๏ธ๐ to show electron distribution!
โ
Keep explanations structured & precise for full marks ๐ฏ๐!
Q. 10. If bromine atom is available in the form of, say, two isotopes 7935Br (49.7%) and 8135 Br (50.3%), calculate the average atomic mass of bromine atom.
Answer:-
โจ Calculation of Average Atomic Mass of Bromine โ๏ธ๐ฌ
A bromine atom exists in two isotopic forms:
๐น 79Br (Atomic Mass = 79 u, Abundance = 49.7%)
๐น 81Br (Atomic Mass = 81 u, Abundance = 50.3%)
๐งฎ Formula for Average Atomic Mass โ๏ธ๐ก
๐ Average Atomic Mass =
[ \frac{(Mass \times Abundance) + (Mass \times Abundance)}{100} ]
๐ Substituting Values
๐ Average Atomic Mass =
[ (79 x 49.7) + (81 x 50.3) ]/100
๐ Average Atomic Mass =
[ 3936.3 + 4084.3 x100 ] = [8020.6/100] = 80.2 u
โ Final Answer:
The average atomic mass of bromine = 80.2 u โ๏ธโจ
๐ฏ Board Exam Tip:
โ
Clearly show step-by-step calculations ๐งฎ.
โ
Define the formula and concept of average atomic mass.
โ
Keep answers neat, structured & well-explained to secure full marks ๐ฏ๐!
Q. 11. The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes 168 X and 18 8 X in the sample?
Answer:-
โจ Calculation of Percentage of Isotopes โ๏ธ๐ฌ
Given:
๐น Average Atomic Mass of X = 16.2 u โ๏ธ
๐น Isotopes Present:
- (168X) (Atomic Mass = 16 u)
- (188X) (Atomic Mass = 18 u)
๐งฎ Formula for Percentage of Isotopes โ๏ธ๐ก
Let x% be the percentage of (168X) and (100 – x)% be the percentage of (188X).
๐ Using weighted average formula:
[ (16(x) + (18 x (100 – x)) = 16.2 x 100 ]
๐ Substituting Values & Solving
[ 16x + 1800 – 18x = 1620 ]
[ -2x + 1800 = 1620 ]
[ -2x = -180 ]
[ x = 90 ]
๐ Percentage of (168X) = 90%
๐ Percentage of (188X) = 100 – 90 = 10%
โ Final Answer:
๐น 90% of the sample consists of (168X) โ๏ธโ
๐น 10% of the sample consists of (188X) โ๏ธโ
๐ฏ Board Exam Tip:
โ
Show step-by-step calculations clearly ๐งฎ.
โ
Define weighted atomic mass formula ๐โจ.
โ
Keep answers structured & precise for full marks ๐ฏ๐!
Q. 12. If Z = 3, what would be the valency of the element? Also, name the element.
Answer:-
โจ Valency and Name of the Element for Z = 3 โ๏ธ๐ฌ
The atomic number (Z) represents the number of protons ๐ in an atom.
๐ Given Z = 3, this means the element has 3 protons, so it is Lithium (Li) ๐๏ธโ๏ธ!
๐น Electronic Configuration of Lithium ๐งฎ
๐ธ Atomic Number = 3 ๐ข
๐ธ Electronic Configuration = 2, 1 โกโกโฐ
๐น Determining Valency โจ
๐ Valency = Number of electrons in the outermost shell ๐โฐ
โ
Lithium has 1 electron in its outermost shell, so its valency = 1! โโจ
โ
Final Answer:
๐น The element is Lithium (Li) โ๏ธ๐๏ธ.
๐น Valency of Lithium = 1! โจ
๐ฏ Board Exam Tip:
โ
Define atomic number & valency ๐.
โ
Show electronic configuration & how valency is determined.
โ
Keep answers structured & precise for full marks ๐ฏ๐!
Q. 13. Composition of the nuclei of two atomic species X and Y are given as under
X | Y | |
Protons | 6 | 6 |
Neutrons | 6 | 8 |
Give the mass numbers of X and Y. What is the relation between the two species?
Answer:-
โจ Mass Number Calculation & Relation Between Species โจ
Let’s analyze atomic species X and Y based on their nuclear composition:
Atomic Species | Protons (๐) | Neutrons (๐) | Mass Number (๐ด = ๐ + ๐) |
---|---|---|---|
X | 6๏ธโฃ | 6๏ธโฃ | 1๏ธโฃ2๏ธโฃ |
Y | 6๏ธโฃ | 8๏ธโฃ | 1๏ธโฃ4๏ธโฃ |
๐ Mass Number Calculation:
Mass number (๐ด) is determined by the sum of protons and neutrons:
[ ๐ด = ๐ + ๐ ]
For X:
๐น ๐ด = 6 + 6 = 12
For Y:
๐น ๐ด = 6 + 8 = 14
๐ Relation Between X and Y:
Since both species have the same number of protons (๐ = 6) but different numbers of neutrons, they are isotopes of the same element.
๐งช Definition of Isotopes:
๐ Isotopes are atomic species with the same atomic number (๐) but different neutron numbers.
๐ Final Answer for Full Marks:
โ X and Y have mass numbers 12 and 14, respectively.
โ X and Y are isotopes because they belong to the same element (๐ = 6) but differ in neutron count.
Q. 14. For the following statements, write T for True and F for False.
(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.
(c) The mass of an electron is about 1/2000 times that of proton.
(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.
Answer:-
โจ True & False Statements โ Answer with Explanation โจ
Hereโs the correct evaluation of the statements for your Class 9 board exams! ๐ฏ
Statement | True / False | Explanation |
---|---|---|
(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons. | โ False | J.J. Thomson proposed the plum pudding model, where electrons were embedded in a positive sphere. The concept of nucleons (protons & neutrons) in the nucleus was introduced later by Rutherford & Chadwick. |
(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral. | โ False | A neutron is not formed by the combination of an electron and a proton. It is a fundamental subatomic particle present in the nucleus with zero charge. |
(c) The mass of an electron is about 1/2000 times that of a proton. | โ True | The mass of an electron is approximately 1/1836 times that of a proton, which is close to 1/2000, hence this statement is considered true for approximation purposes. โ๏ธ |
(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine. | โ False | Tincture iodine (used as an antiseptic) contains iodine dissolved in alcohol, but radioactive isotopes of iodine (like I-131) are used in medical treatments (not in tincture iodine). ๐ |
๐ Final Answer for Full Marks:
โ (a) False
โ (b) False
โ (c) True
โ (d) False
Put tick (ยธ) against correct choice and cross (ร) against wrong choice in questions 15, 16 and 17
Q. 15. Rutherfordโs alpha-particle scattering experiment was responsible for the discovery of
(a) Atomic Nucleus
(b) Electron
(c) Proton
(d) Neutron
Answer:-
โจ Rutherfordโs Alpha-Particle Scattering Experiment โ Discovery โจ
๐ Question: Rutherfordโs alpha-particle scattering experiment was responsible for the discovery of:
(a) Atomic Nucleus
(b) Electron
(c) Proton
(d) Neutron
โ Correct Answer: (a) Atomic Nucleus
๐ Explanation:
๐ฌ Rutherfordโs gold foil experiment demonstrated that:
โ Atoms have a small, dense, positively charged nucleus at their center.
โ Most of the atomโs space is empty, allowing alpha particles to pass through without deflection.
โ Some alpha particles deflected at large angles, proving the presence of a central nucleus that repelled them.
๐ข Why Not Others?
โ Electron: Discovered by J.J. Thomson in his cathode ray experiment.
โ Proton: Rutherford later proposed the protonโs existence, but his experiment directly led to the nucleus discovery.
โ Neutron: Discovered later by James Chadwick in 1932.
๐ Final Answer for Full Marks:
โ Rutherfordโs experiment led to the discovery of the atomic nucleus.
โ Correct choice: (a) Atomic Nucleus.
Q. 16. Isotopes of an element have
(a) the same physical properties
(b) different chemical properties
(c) different number of neutrons
(d) different atomic numbers.
Answer:-
โจ Understanding Isotopes โ Answer & Explanation โจ
๐ Question: Isotopes of an element have:
(a) The same physical properties
(b) Different chemical properties
(c) Different number of neutrons
(d) Different atomic numbers
โ Correct Answer: (c) Different number of neutrons
๐ Explanation:
๐งช Isotopes are atoms of the same element that have:
โ Same atomic number (๐) โ Same number of protons
โ Different number of neutrons โ Different mass numbers
๐ข Why Not Others?
โ (a) Same physical properties:
๐ Some physical properties do vary, especially those related to mass (like density & boiling point). So this is incorrect.
โ (b) Different chemical properties:
๐ Isotopes have the same number of electrons and protons, so their chemical properties remain the same.
โ (d) Different atomic numbers:
๐ Atomic number is always the same for isotopes of an element. If atomic number changes, it becomes a different element, not an isotope.
๐ Final Answer for Full Marks:
โ Isotopes of an element have different numbers of neutrons.
โ Correct choice: (c) Different number of neutrons.
Q. 17. Number of valence electrons in Clโ ion are:
(a) 16
(b) 8
(c) 17
(d) 18
Answer:-
โจ Valence Electrons in Clโป Ion โ Answer & Explanation โจ
๐ Question: The number of valence electrons in Clโป ion are:
(a) 16
(b) 8
(c) 17
(d) 18
โ Correct Answer: (b) 8
๐ Explanation:
๐งช Chlorine (Cl) Atomic Number = 17
โ In a neutral chlorine atom, the electron configuration is 2, 8, 7 โ 7 valence electrons.
โ When chlorine gains 1 electron to form Clโป ion, it has 8 valence electrons (like noble gas configuration).
๐ข Why Not Others?
โ (a) 16: Total electrons in Clโป are 18, but valence electrons refer to only outermost shell electrons.
โ (c) 17: Chlorine has 17 protons, but the number of electrons in the valence shell changes when forming Clโป.
โ (d) 18: Total electrons in Clโป ion = 18, but valence electrons = 8.
๐ Final Answer for Full Marks:
โ Clโป ion has 8 valence electrons.
โ Correct choice: (b) 8.
Q. 18. ๐ Question: Which one of the following is the correct electronic configuration of sodium (Na)?
(a) 2,8
(b) 8,2,1
(c) 2,1,8
(d) 2,8,1
Answer:-
โจ Electronic Configuration of Sodium (Na) โ Answer & Explanation โจ
โ Correct Answer: (d) 2,8,1
๐ Explanation:
๐งช Sodium (Na) Atomic Number = 11
โ The atomic number represents the total number of electrons in a neutral atom of sodium.
โ Electrons are arranged in shells following the 2, 8, 18 rule for distribution.
๐น Step-by-Step Electron Distribution:
1๏ธโฃ First shell (K): Max capacity = 2 electrons โ 2
2๏ธโฃ Second shell (L): Max capacity = 8 electrons โ 8
3๏ธโฃ Third shell (M): Remaining 1 electron โ 1
๐ข Why Not Others?
โ (a) 2,8: Incorrect because sodium has 11 electrons, not just 10.
โ (b) 8,2,1: Incorrect as electron filling follows 2,8,1 order, not 8 first.
โ (c) 2,1,8: Incorrect as electrons follow K โ L โ M shell filling rule.
๐ Final Answer for Full Marks:
โ Sodiumโs electronic configuration is 2,8,1.
โ Correct choice: (d) 2,8,1.
Q. 19. Complete the following table.

Answer:-
Here’s the completed table with all missing values filled in for clarity! โจ
Atomic Number | Mass Number | Number of Neutrons | Number of Protons | Number of Electrons | Name of the Atomic Species |
---|---|---|---|---|---|
9 | 19 | 10 | 9 | 9 | Fluorine |
16 | 32 | 16 | 16 | 16 | Sulphur |
12 | 24 | 12 | 12 | 12 | Magnesium |
1 | 2 | 1 | 1 | 1 | Deuterium |
1 | 1 | 0 | 1 | 1 | Hydrogen |
๐ข How was the table completed?
โ Number of neutrons = Mass Number – Atomic Number
โ Number of protons = Atomic Number
โ Number of electrons = Atomic Number (for neutral atoms)